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0.5x^2-2.5x-42=0
a = 0.5; b = -2.5; c = -42;
Δ = b2-4ac
Δ = -2.52-4·0.5·(-42)
Δ = 90.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.5)-\sqrt{90.25}}{2*0.5}=\frac{2.5-\sqrt{90.25}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.5)+\sqrt{90.25}}{2*0.5}=\frac{2.5+\sqrt{90.25}}{1} $
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